Q. No.4
What is the perimeter of ALBC
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Answer:
Perimeter of ΔLBC=16cm
Step-by-step explanation:
In ΔABC
AB=8cm. AC=10cm
By Pythogoras theoram,
BC=6cm
By Midpoint theoram,
ML=1/2(BC)
Therefore ML=3cm
In ΔMLB
By Pythogoras theoram,
BL=5cm
Therefore, Perimeter of ΔLBC=5+5+6= 16cm.
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