Question

Q no 42.The electric field on a point charge is situate.......

Answer 1

$t = pe \sin( \alpha )$

here e= 4*10^5

t= 8√3

alpha = 60 degree

now dipole moment p= 8√3/4*10^5*sin60

p= 4*10^-5

p = q*l

q = 4*10^-5/4*10^-2

q= 10^-3