Physics, asked by srikanthiyaar, 6 months ago

Q.No: 5
A charged particle (+2.2 pC) moves along a the x
axis in an E-field (22 N/m) that is also directed
along the x-axis. Determine both the change in
electric potential energy (in MeV) for the particle
when it undergoes a displacement from x=2 m to x
= 20 m.
A) -5.4 x 109 eV
B) -1.4 x 109 eV
C) 4.4 x 10^9 eV
D) None​

Answers

Answered by vaishnavisenthil
0

Answer:

Explanatio -5.4 x 109 eV

B) -1.4 x 109 eV

C) 4.4 x 10^9 eV

D) None​n:

Q.No: 5

A charged particle (+2.2 pC) moves along a the x

axis in an E-field (22 N/m) that is also directed

along the x-axis. Determine both the change in

electric potential energy (in MeV) for the particle

when it undergoes a displacement from x=2 m to x

= 20 m.

A) -5.4 x 109 eV

B) -1.4 x 109 eV

C) 4.4 x 10^9 eV

D) None​

Answered by AnushkaMate56
0

Answer:

Negative charge will tend to move towards higher electric potential because of the strong Coulomb attraction. Hence it moves towards a position of higher electric potential.

Potential energy of a system of fixed point charges is equal to the work that must be done by an external agent to bring each charge in from infinite distance. Hence the charge will try to tend to move towards low potential energy.

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