Question

Q. No.5:- A rectangular sheet of paper is 11 3/4 cm long
and 10 1/2 cm wide. Find perimeter and also find its area.​

Answer 1

Answer:

Length = 11.75 cm

width = 10.5 cm

perimeter = 2* (length +width) = 2*(11.75+10.5) = 44.50 cm = 44 1/2 cm

area = length*width = 11.75*10.5 = 123.375 = 123 3/8 cm^2

Answer 2

$\huge{ \pink{ \bold{ \underline{ \underline{Question: - }}}}}$

$\small{ \green{ \bold{A \: rectangular \: sheet \: of \: paper \: is \: 11 \: 3/4 \: cm \: long \: and \: 10 \: 1/2 \: cm \: wide. \: Find \: perimeter \: and \: also \: find \: its \: area.}}}$

$\huge{ \pink{ \bold{ \underline{ \underline{Answer:-}}}}}$

$\small{ \green{ \bold{lenght = 11 \frac{3}{4} \: cm \: and \: breadth = 10 \frac{1}{2} \: cm}}}$

$\small{ \pink{ \bold{Primeter \: of \: rectangle = 2(lenght + breadth)}}}$

$\small{ \green{ \bold{Primeter = 2(11 \: \frac{3}{4} + 10 \: \frac{1}{2})}}}$

$\small{ \green{ \bold{Primeter = 2( \frac{47}{4} + \frac{21}{2})}}}$

$\small{ \green{ \bold{Primeter = 2( \frac{47 + 42}{4})}}}$

$\small{ \green{ \bold{Primeter = (2 \times \frac{89}{4}) }}}$

$\small{ \green{ \bold{Primeter = \frac{89}{2} \: cm \: or \: 44 \frac{1}{2} \: cm}}}$

$\small{ \pink{ \bold{Area \: of \: rectangle = (lenght \times breadth)}}}$

$\small{ \green{ \bold{Area = (11 \: \frac{3}{4} \times 10 \: \frac{1}{2})}}}$

$\small{ \green{ \bold{Area = ( \frac{47}{4} \times \frac{21}{2})}}}$

$\small{ \green{ \bold{Area = \frac{947}{8} \: {cm}^{2} \: or \: 118 \frac{3}{8} \: {cm}^{2} }}}$