Physics, asked by carzyboyvenky198, 4 months ago

Q no: 54
A block of mass 1kg moving with a speed of
4ms-1, collides with another block of mass
2kg which is at rest. The lighter block comes
to rest after collision. The loss in KE of the
system is
-A)
81​

Answers

Answered by himanthnukala
3

Answer:

see up.............................

Attachments:
Answered by naughty3036
0

Answer:

loss in K.E. is 4J because after collision 2 kg moves with 2m/s and its k.e.is 4 initially it was 8 J

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