Math, asked by vaibhavpick466, 11 months ago

Q. No. 6 please answer very fast. Its urgent

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Answered by pmtibrahim18
0

let us take the number of articles as "x"

cost of production = "y"

as per the given condition.

y = 3+2x                   eq.1

x+ y = 90                  eq.2

putting y's value of eq. 1 in 2

x + 2x = 90

3x = 90

x = 30

y = 3+60 = 63


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pmtibrahim18: I hope it is right
vaibhavpick466: its wrong bro
pmtibrahim18: oh
Anonymous: No problem, you can edit your answer.
Answered by Anonymous
1
Let the number of articles produced on certain day be x.

Cost of production of each article = 3 + 2x

Total cost = Number of articles × cost of each article

Total cost = x ( 3 + 2x )

90 = 3x + 2x^2

0 = 2x^2 + 3x - 90

0 = 2x^2 + 15x - 12x - 90

0 = x ( 2x + 15 ) - 6 ( 2x - 15 )

0 = ( x - 6 ) ( 2x + 15 )

( x - 6 ) = 0 and ( 2x + 15 ) = 0

x = 6 or - 15 / 2

So, Number of articles produced = 6

Cost of each article = 3 + 2 x = 3 + 2(6)

= 12 + 3 = Rs.15


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