Q no 7 angle between a vect and b vector
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dot product nikal kar formula se angle find out kar sakte h
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Answer:
vector A=4i^+6j^-3k^
|vector A|=√(4²+6²+(-3)²=√61
vector B=-2i^-5j^+7k^
|vector B|= √(4+25+49=√78
Vector A.vector B=|Al|B| cos@
cos@=(4i^+6j^-3k^)(-2i^-5j^+7k^)/(√61)(√78
cos@=(-8-30-21)/√4758=-59/68.978=-0.8553
cos@=cos(148.792)
@=148.782°
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