Math, asked by khanmehjoor, 7 months ago

Q. NO7- How many three digits numbers are divisible by 8?

Answers

Answered by Lovelyfriend
2

⟹994=98+7n

⟹994=98+7n⟹7n=994−98

⟹994=98+7n⟹7n=994−98⟹7n=896

⟹994=98+7n⟹7n=994−98⟹7n=896⟹n=7896

⟹994=98+7n⟹7n=994−98⟹7n=896⟹n=7896⟹n=128

an=a1+(n−1)d

an=a1+(n−1)d⟹an=105+(n−1)7

an=a1+(n−1)d⟹an=105+(n−1)7⟹an=105+7n−7

an=a1+(n−1)d⟹an=105+(n−1)7⟹an=105+7n−7⟹an=98+7n...….eq(1)

Answered by vrinda7618
0

Answer:

The Rule for 8: a number is divisible by 8 if the last three digits are evenly divisible by 8. For example, 17216. The last three digits are 216 and it is divisible by 8.

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