q.no9...............
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Answer:
K = 4
Step-by-step explanation:
IF THE GIVEN ARE COLLINEAR THEN AREA ENCLOSE BY THEM IS ZERO 0
AREA ENCLOSED BY THEM = 1/2 (X1(Y2-Y3)+X2(Y3-Y2)+X3(Y1-Y2))
0 = I/2( 7(1-K)+ 5(K-(-2)) + 3 (-2-1)) = 1/2(7-7K + 5(k+2) + 3(-3))
= 1/2(7 - 7K + 5K + 10 -9 ) = 1/2(-2K + 8)
0 = -2K+8(Multiply both sided with 2)
-8 = -2k
k = 4
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hey mate here's your answer
hope it helps.....
hope it helps.....
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