Question

Q.Nos. (11-15) Fill in the blanks with appropriate answer
proton is accelerated through a potential difference V, subjected to a
uniform magnetic field acting normal to the velocity of the proton. If the
potential difference is doubled, the radius of the circular path described by
the proton in the magnetic field will change how​

Answer 1

R= MV/QB

mv= √2mqV, where V is potential difference

R∝ √V

Radius will become √2 times.