Math, asked by KnightLyfe, 1 month ago

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On a morning walk, three people step of together and their steps measure 40 cm, 42 cm and 45 cm respectively. What is the minimum distance each should walk, so that each can covers the same distance in complete steps?

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Answers

Answered by MaTaehyung
5

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Since, the three persons start walking together.

Therefore, The minimum distance covered by each of them in complete steps = LCM of the measures of their steps

= LCM (40, 42, 45)

40 = 2 x 2 x 2 x 5 = 2³ x 5

42 = 2 x 3 x 7

45 = 3 x 3 x 5 = 3² x 5

=> LCM (40, 42, 45) = 2³x 3² x 5 x 7

= 2520

=> Each person should walk a minimum distance of 2520 cm in complete steps.

I hope this will be correct and it will help you ✨⚡

Answered by itzbangtanarmy7
24

Answer:

Since, the three persons start walking together.

Therefore, The minimum distance covered by each of them in complete steps = LCM of the measures of their steps = LCM (40, 42, 45)

40 = 2 x 2 x 2 x 5 = 23 x 5

42 = 2 x 3 x 7

45 = 3 x 3 x 5 = 32 x 5

=> LCM (40, 42, 45) = 23 x 32 x 5 x 7 = 2520

=> Each person should walk a minimum distance of 2520 cm in complete steps

hope this helps you :-(

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