Question

Q. One angle of a triangleis greater than than sum of the other two. What can you say about the measure pf this angle ? What type of a triangleis this ? Solve the Solution.​

Answer 1

Answer:

Consider ABC as a triangle

According to the question it can be written as

∠B>∠A+∠C....(1)

We know that the sum of all the angles in a triangle is 180

∘

.

So we can write it as

∠A+∠B+∠C=180

∘

So we get

∠A+∠C=180

∘

−∠B

Substituting ∠A+∠C in equation (1) we get

∠B>180

∘

−∠B

Add ∠B to both the sides of the equatio

So we get

∠B+∠B>180

∘

−∠B+∠B

By addition we get

2∠B>180

∘

By division we get

∠B>180/2

∠B>90

∘

So we know that ∠B>90

∘

which means that ∠B is an obtuse angle

Therefore, it is proved that the triangle ABC is obtuse angled.

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Answer 2

angle a > angle b+ angle c

adding a on both sides.

angle a + angle a > angle a +b+c

2 angle a > 180°

angle a > 90° so, angle a is obtuse