Question

(Q^p)-(p^Q)=
a)1
b)-1
c)0
d)2

Answer 1

Answer:

Assume Q be 1 and P be 1

Step-by-step explanation:

So, (Q^P) - (P^Q)

• (1^1) -(1^1)

1. 1 -1 = 0
2. Assume Q be 2 & P be 1.

• 2 -1 = 1

3. assume Q be 2 & P be 3.

then, AtQ; (2)^3 - (3)^2

• 8 - 9 = -1

4. Assume Q be 3 & P be 1

then; ATQ, (3)^1 - (1)^2

• 3 - 1 = 2

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