Question

Q Peter took a loan from a bank
106 whose first installment was $400. If
he increases the installment by $10
every month, what amount will he
pay in the 25th installment?
Ops: A.
$650
B.
$640
C. • $540
D.
$550
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Answer 1

Answer:

B. 640

Step-by-step explanation:

Given,

First installment = rs.400

Installment increases by rs.10 every month

So, Second Installment = Rs.400+Rs.10 = Rs.410

Third Installment = Rs.410+Rs.10= Rs.420

So, It forms an A.P. : 400,410,420,........

Here, First term a = Rs.400

common difference d = rs.10

Formula for nth therm = An=a+(n-1)*d

Substitute, n = 25,

a25 = 400 + (25-1) * 10

a25 = 400 + (24 * 10)

a25 = 400 + 240

a25 = 640.

Hence Peter will pay Rs. 640 in the 25th installment.

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Answer 2

Answer:

First installment = rs.200

Installment increases by rs.5 every month

So, Second Installment = Rs.200+Rs.5 = Rs.205

Third Installment = Rs.205+Rs.5= Rs.210

So, It forms an AP : 200,205,210, .............

So, First term = a = Rs.200

d = common difference = rs.5

Formula of nth term =

Substitute n = 25

Hence He will pay Rs.320 in 25th installment .

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