Question

Q pls give complete soln Q 52

Answer 1

[Nickeldimethylglyoximate = say NDMG ]
1 molecule of NDMG contain → 1 atom of Ni.
=> 1 mole NDMG contains → 1 mol Ni atoms.
289 g of NDMG contains → 59 g of Ni.
then,
0.259 g of NDMG will contain →
(59/289)×0.259 = 0.0528 g.
this means that the steel sample (1.502g) is having 0.0528g of Ni.
then % of Ni in steel sample is :
( 0.0528/1.502)×100 = 3.520 %.
Hence (b) is the correct option!