Q pls give the complete soln..
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The correct option is (c)
The given equations can be written as
- x + cy + bz = 0 ----------- (i)
cx -y + az = 0 -------------(ii)
bx + ay - z = 0 --------------(iii)
By cross multiplication eq (i) and (ii),
x/ ac + b = y/bc + a = z/ 1 - c^2 = K ( let's say)
x = K(ac + b)
y= K(bc + a) z= K(1 – c^2)
Putting the values of x,y, z in eq (iii)
b.K( ac+ b) + a.K( bc+ a) - k( 1 - c^2) = 0
K( a^2 + b^2 + c^2 + 2abc - 1) = 0
But x, y , z are not equal to zero.. So, K is also not equal to zero.
a^2 + b^2 + c^2 + 2abc = 1
correct option is C
The given equations can be written as
- x + cy + bz = 0 ----------- (i)
cx -y + az = 0 -------------(ii)
bx + ay - z = 0 --------------(iii)
By cross multiplication eq (i) and (ii),
x/ ac + b = y/bc + a = z/ 1 - c^2 = K ( let's say)
x = K(ac + b)
y= K(bc + a) z= K(1 – c^2)
Putting the values of x,y, z in eq (iii)
b.K( ac+ b) + a.K( bc+ a) - k( 1 - c^2) = 0
K( a^2 + b^2 + c^2 + 2abc - 1) = 0
But x, y , z are not equal to zero.. So, K is also not equal to zero.
a^2 + b^2 + c^2 + 2abc = 1
correct option is C
Anonymous:
hehe ty....
good explanation
bella the great.. ;)
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