Math, asked by Sahkfd4584, 1 day ago

Q.Prove that :-
log6×log8 to the base root 2=1

Answers

Answered by chaitaliganguly207
0

Answer:

logb(x) = y, and x = logb(bx)

logb(x) = y and x = by

Step-by-step explanation:

log8 (2) = 0.333333333

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