Question

Q- Prove that some of square of two odd positive

Q- Show that for any positive integer n, n³-n is divisible by 6



pls ;-;
don't spam ​

Answer 1

ques2- ans - Case 2: Consider n = 2q + 1

Since, n (n – 1) (n + 1) is divisible by 2 and 3. Therefore, as per the divisibility rule of 6, the given number is divisible by six. n3 – n = n (n – 1) (n + 1) is divisible by 6.

Answer 2

Answer:

hey senpai how you doin?