Question

Q)Prove that the line of centres of two intersecting circles subtends equal angles at the two points of intersection.
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Answer 1

ln ∆ACB and ∆ADB

AC=AD(radii of the circle with centre A)

AC=BD(radii of the circle with centre B)

AB=AB(common)

so,

by SSS criteria of congruency

∆ACB=∆ADB

angleACB=angle ADB