Q) Prove that the medians of an equilateral triangle are equal.
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Step-by-step explanation:
Let ΔABC be an equilateral triangle with AD,BE and CF as its medians.
Let AB=AC=BC=x units
In triangles BFC and CEB, we have
BF=CE [∵AB=AC⇒ 1/2
AB=
2
1
AC⇒BF=CE]
∠ABC=∠ACB [Each equal to 60
∘
]
and, BC=BC [Common]
So by SAS congruence criterion, we obtain
ΔBFC≅ΔCEB⇒BE=CF
Similarly, we have AB=BE
Hence, AD=BE=CF
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