Q. Prove that triangle AOB congruent to triangle DOC by ASA Congruency Condition.
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Step-by-step explanation:
In ΔAOB and ΔDOC,
∠BAO = ∠CDO (Alternate interior angles, AB || CD)
AO = DO (Given, O is the midpoint of AD)
∠AOB = ∠DOC (Vertically opposite angles)
∴ By ASA congruence criteria
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