Question

Q. Prove the following identity:

Answer 1

Answer:

this is the solution...

$\frac{ {tan}^{2}a - (1 - {cos}^{2}a) }{ {sin}^{2}a }$

$\frac{ {tan}^{2}a - {sin}^{2}a }{ {sin}^{2} a}$

$\frac{ {tan}^{2} a}{ {sin}^{2}a } - \frac{ {sin}^{2}a }{ {sin}^{2}a }$

$\frac{ \frac{ {sin}^{2}a }{ {cos}^{2}a } }{ {sin}^{2}a } - 1$

${sec}^{2} a - 1 = {tan}^{2} a$

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