Math, asked by raghubir68, 4 months ago

q-q/3+1/3=q/5-1/5+q
Find 'q'.

PLEASE HELP​

Answers

Answered by jeevikaanthwal9a2103
0

How to solve your question

Your question is

1

3

+

1

3

=

5

1

1

5

+

q-1 \cdot \frac{q}{3}+\frac{1}{3}=\frac{q}{5}-1 \cdot \frac{1}{5}+q

q−1⋅3q+31=5q−1⋅51+q

Solve

1

Combine multiplied terms into a single fraction

1

3

+

1

3

=

5

1

1

5

+

+

3

+

1

3

=

5

1

1

5

+

2

Multiply the numbers

+

3

+

1

3

=

5

1

1

5

+

+

3

+

1

3

=

5

1

5

+

3

Subtract

1

3

\frac{1}{3}

31

from both sides of the equation

+

3

+

1

3

=

5

1

5

+

+

3

+

1

3

1

3

=

5

1

5

+

1

3

4

Simplify

Subtract the numbers

Subtract the numbers

+

3

=

5

8

1

5

+

5

Subtract

q

q

from both sides of the equation

+

3

=

5

8

1

5

+

+

3

=

5

8

1

5

+

6

Simplify

Combine like terms

Combine like terms

3

=

5

8

1

5

7

Multiply all terms by the same value to eliminate fraction denominators

3

=

5

8

1

5

3

5

3

=

3

5

(

5

8

1

5

)

8

Simplify

Cancel multiplied terms that are in the denominator

Multiply the numbers

Multiply the numbers

Distribute

Combine multiplied terms into a single fraction

Cancel terms that are in both the numerator and denominator

5

=

3

8

9

Subtract

3

3q

3q

from both sides of the equation

5

=

3

8

5

3

=

3

8

3

10

Simplify

Combine like terms

Combine like terms

8

=

8

11

Divide both sides of the equation by the same term

8

=

8

8

8

=

8

8

12

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

1

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