Question

Q. Q. Construct Δ PQR, QR = 6.2 cm, PQ = 4.6 cm, PR = 4.9 cm. Measures and state the measure of angle PQR.

(Draw And Show)

Class 7 maths​

Answer 1

Answer:

Step-by-step explanation:

onstruct ΔPQR, in which QR = 4.2cm  m∠Q = 40∘ and PQ + PR = 8.5cm

ANSWER:

Steps of constructions:

(1) Draw seg QR of length 4.2 cm.

(2) Draw ray QT such that ∠RQT = 40°.

(3) Mark point S on ray QT such that QS = 8.5 cm

(4) Draw seg RS.

(5) Construct the perpendicular bisector of seg RS .

(6) Name the point of intersection of ray QS and the perpendicular bisector of RS as P.

(7) Draw seg PR.

Therefore, △ABC is the required triangle

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Question 2:

Construct  Δ XYZ, in which YZ = 6 cm, XY + XZ = 9 cm. ∠XYZ = 50∘

ANSWER:

Steps of constructions:

(1) Draw seg YZ of length 6 cm.

(2) Draw ray YV such that ∠ZYV = 50°.

(3) Mark point W on ray YV such that YW = 9 cm

(4) Draw seg WZ.

(5) Construct the perpendicular bisector of seg WZ .

(6) Name the point of intersection of ray YW and the perpendicular bisector of WZ as X.

(7) Draw seg XZ.

Therefore, △XYZ is the required triangle.