Question

Qᴜᴇsᴛɪᴏɴ

Find a relation between x and y such that the point (x,y) is equidistant from the point (3,6) and (−3,4).

ᴊᴜɴɪᴏʀs ᴅᴏɴ'ᴛ ᴀɴsᴡᴇʀ❌
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Answer 1

➽Sᴇᴇ Tʜᴇ Aʙᴏᴠᴇ Aᴛᴛᴀᴄʜᴍᴇɴᴛ⇡

Tʜᴀɴᴋs♡.

Answer 2

Answer:

SIMPLE

DISTANCE FORMULA

Let the point P(x,y) is equidistant from the points A(3,6)and B(−3,4)

∴PA=PB

PA²=PB²

By using the distance formula

=

(x 2 −x 1)²+(y 2 −y 1)² we have

⇒ (x−3)²+(y−6)² =(x+3)²+(y−4)²

⇒(x−3) ² +(y−6)²=(x+3) ²+(y−4)²

⇒x² −6x+9+y²−12y+36=x 2 +6x+9+y² −8y+16

⇒−6x−6x−12y+8y+36−16=0

⇒−12x−4y+20=0

⇒3x+y−5=0

Hence this is a relation between x and y.