Question

Q-s Find the value of k for the following
quadratic equation so that it has tão
bital and equal roots.
5xsquare – 2 kx +20 = 0​

Answer 1

Answer:

$\huge\mathbb\red{ k = 10}$

Step-by-step explanation:

TO HAVE EQUAL ROOTS:-

b² - 4ac = 0

Given:

$\bf\huge\red{5x² -2kx + 20 = 0}$

Solution

$\sf\bf {b}^{2} - 4ac = 0 \\ \\ \sf\bf { (- 2k)}^{2} - 4(5)(20) = 0 \\ \\ \sf\bf 4 {k}^{2} - 400 = 0 \\ \\ \bf 4 {k}^{2} = 400 \\ \\ \bf {k}^{2} = \frac{400}{4} \\ \\ \bf {k}^{2} = 100 \\ \\ \bf k = \sqrt{100} \\ \\ \bf\huge \fbox\purple{k = 10 \: answer}$

$\huge\mathrm\green{Hence\: the\: value\: of \:K \: is \: 10}$

Answer 2

ANSWER

5x^-2kx+20=0

5x^+20=2kx

5x^+20/2=kx

5x^+10=kx

5x^+10/x=0

5x+10=0

5x=10

x=10/5

x=2

x=2 value put in to 5x^-2kx+20=0

5×2^-2k×2+20=0

5×4-4k+20=0

20-4k+20=0

(-4k)=(-20)-20

(-4k)=(-40)

(-k)=(-10)

k=10

Explanation

Meaning of ^ is square