Physics, asked by zacknight47, 4 months ago

•Q-ᴀ ᴄɪʀᴄᴜʟᴀʀ ᴄᴏɪʟ ᴏғ ᴡɪʀᴇ ᴄᴏɴsɪsᴛɪɴɢ ᴏғ 100 ᴛᴜʀɴs, ᴇᴀᴄʜ ᴏғ ʀᴀᴅɪᴜs 8.0 ᴄᴍ ᴄᴀʀʀɪᴇs ᴀ ᴄᴜʀʀᴇɴᴛ ᴏғ 0.40 ᴀ. ᴡʜᴀᴛ ɪs ᴛʜᴇ ᴍᴀɢɴɪᴛᴜᴅᴇ ᴏғ ᴛʜᴇ ᴍᴀɢɴᴇᴛɪᴄ ғɪᴇʟᴅ ʙ ᴀᴛ ᴛʜᴇ ᴄᴇɴᴛʀᴇ ᴏғ ᴛʜᴇ ᴄᴏɪʟ?​


arushi6699: hii

Answers

Answered by RoyalQueen007
7

Look at the pictures !!

\huge\fbox\red{A}\fbox\pink{n}\fbox\purple{S}\fbox\green{w}\fbox\blue{E}\fbox\orange{r}

Attachments:
Answered by Anonymous
10

Answer:

Number of turns on the circular coil, n = 100

Radius of each turn, r = 8.0 cm = 0.08m

Current flowing in the coil, I = 0.4A

Magnitude of the magnetic field at the centre of the coil is given by the relation,

| B | = μ0 2πnI / 4π r

Where,

μ0 = Permeability of free space

 =  4\pi \times  {10}^{ - 7} t \:  \: m \:  {a}^{ - 1}

 |b|  = 4\pi \times  {10}^{ - 7 }  \times 2\pi \times 100 \times 0.4 \div 4\pi \times 0.08

 = 3.14 \times  {10}^{ - 4} t

Hence, the magnitude of the magnetic field is

 = 3.14 \times  {10}^{ - 4} t

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