Q-ᴀ ᴄɪʀᴄᴜʟᴀʀ ᴄᴏɪʟ ᴏғ ᴡɪʀᴇ ᴄᴏɴsɪsᴛɪɴɢ ᴏғ 100 ᴛᴜʀɴs, ᴇᴀᴄʜ ᴏғ ʀᴀᴅɪᴜs 8.0 ᴄᴍ ᴄᴀʀʀɪᴇs ᴀ ᴄᴜʀʀᴇɴᴛ ᴏғ 0.40 ᴀ. ᴡʜᴀᴛ ɪs ᴛʜᴇ ᴍᴀɢɴɪᴛᴜᴅᴇ ᴏғ ᴛʜᴇ ᴍᴀɢɴᴇᴛɪᴄ ғɪᴇʟᴅ ʙ ᴀᴛ ᴛʜᴇ ᴄᴇɴᴛʀᴇ ᴏғ ᴛʜᴇ ᴄᴏɪʟ?
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Answer:
3.14×10‐⁴T
Explanation:
Number of turns on the circular coil, n = 100
Radius of each turn, r = 8.0 cm = 0.08 m
Current flowing in the coil, I = 0.4 A
Magnitude of the magnetic field at the centre of the coil is given by the relation,
| B | = μ0 2πnI / 4π r
Where,
μ0 = Permeability of free space
= 4π × 10–7 T m A–1
| B | = 4π x 10-7 x 2π x 100 x 0.4 / 4π x 0.08
= 3.14 x 10-4 T
Hence, the magnitude of the magnetic field is 3.14 × 10–4 T.
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