Question

Q. Show that a perfect square never leaves remainder 2 on dividing by 3. ​

Answer 1

Answer:

Please refer the attachment for the answer.

Hope the answer helps you.

Answer 2

We know,

Remainder formula: Dividend = Quotient x Divisor + Remainder.

Let x=6q+3

Then, x

2

=(6q+3)

2

=36q

2

+36q+9

=6(6q

2

+6q+1)+3

Thus, when x

2

is divided by 6, then remainder =3.

hope it helps you ✌️✅✅✅