Q .Show that in case of one dimensional elastic collision of two bodies relative velocity of separation
is equal to the relative velocity of approach. How does coefficient of restitution decides the nature of
Collison.
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Explanation:
When 2 elastic bodies are separated by a distance "m" such that the center of the elastic string is O and each ends are A and B respectively, then OA = OB = m/2 and the time taken for the collisions are also same so
AO/t = Velocity(a)
BO/t = Velocity(b)
Since AO = BO, t = t
Velocity(a) = Velocity (b)
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