Q.
Show that : sin (B-C) cos (A - D) + sin (C – A) cos (B – D)
+ sin (A - B) cos (C - D) =0
please guys solve it I will mark as Brainliest and I will very proud of you!
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i hope u will better understand how to solve tbis quistion with the help of formula......
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Sin( B-C) cos ( A-D)+ sin(C-A)cos(B-D)+sin(A-B) cos(C-D
= (SinB cosC -CosB SinC) (CosA CosD+ SinA SinD)+ (SinC CosA-CosC SinA) ( CosB CosD+ SinB SinD) +( SinA CosB-CosA SinB) (CosC CosD+ SinC SinD)
=[CosACosCCosDSinB-CosACosBCosDSinC] +[SinASinBSinDCosC-SinASinCSinDCosB] + [CosACosBCosDSinC-CosCCosBCosDSinA] + [SinBSinCSinDCosA-SinASinBSinDCosC] + [CosBCosCCosDSinA-CosACosCCosDSinB] +[ SinASinCSinDCosB-SinBSinCSinDCosA]
(-) formula cut by plus so the answer is
= 0
L.H.S= R.H. S
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