Question

Q simplify
${ \bf a) \frac{16 {y}^{2} + 80 {y}^{2} - 20y}{4y} } \\ \\ \bf \: b) \: \frac{(1 + a)(1 + b)(3)}{3(1 + a)} \\ \\ \bf \: c \: \frac{10 {x}^{2} + 15x}{5x}$
Note - use the easiest method _/\_​

Answer 1

$\large\underline{\sf{Solution-a}}$

Given expression is

$\rm \: \frac{16 {y}^{2} + 80 {y}^{2} - 20y}{4y}$

$\rm \: = \: \frac{96{y}^{2} - 20y}{4y}$

$\rm \: = \: \frac{96{y}^{2}}{4y} - \frac{20y}{4y}$

$\rm \: = \:24y - 5$

So,

$\rm\implies \:\boxed{\sf{  \:\rm \: \frac{16 {y}^{2} + 80 {y}^{2} - 20y}{4y} = 24y - 5 \: \: }}$

$\large\underline{\sf{Solution-b}}$

Given expression is

$\rm \: \frac{(1 + a)(1 + b)(3)}{3(1 + a)}$

can be re-arranged as

$\rm \: = \:\frac{\cancel3 \: \cancel{(1 + a)} \: (1 + b)}{\cancel3 \: \cancel{(1 + a)}}$

$\rm \: = \:1 + b$

Hence,

$\rm\implies \:\boxed{\sf{  \:\rm \: \frac{(1 + a)(1 + b)(3)}{3(1 + a)} = 1 + b \: \: }}$

$\large\underline{\sf{Solution-c}}$

Given expression is

$\rm \: \frac{10 {x}^{2} + 15x}{5x}$

$\rm \: = \:\frac{10 {x}^{2}}{5x} + \frac{15x}{5x}$

$\rm \: = \:2x + 3$

Hence,

$\rm\implies \:\boxed{\sf{  \:\rm \: \frac{10 {x}^{2} + 15x}{5x} = 2x + 3 \: \: }}$

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Additional Information :-

$\boxed{\sf{  \:\rm \: {(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \: \: }}$

$\boxed{\sf{  \:\rm \: {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \: \: }}$

$\boxed{\sf{  \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }}$

$\boxed{\sf{  \:\rm \: (x + a)(x + b) = {x}^{2} + (a + b)x + ab \: \: }}$

$\boxed{\sf{  \:\rm \: {x}^{m} \div {x}^{n} = {x}^{m - n} \: \: }}$

$\boxed{\sf{  \:\rm \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: \: }}$

$\boxed{\sf{  \:\rm \: {( {x}^{m} )}^{n} = {x}^{mn} \: \: }}$

$\boxed{\sf{  \:\rm \: {x}^{0} \: = \: 1 \: \: }}$

$\boxed{\sf{  \:\rm \: {x}^{ - n} \: = \: \frac{1}{ {x}^{n} } \: \: }}$

Answer 2

Answer:

Kepler-452b is a super-Earth exoplanet orbiting within the inner edge of the habitable zone of the Sun-like star Kepler-452, and is the only planet in the system discovered by Kepler. It is located about 1,402 light-years from Earth in the constellation of Cygnus.

Hi mam

i was not reading your ch.at on that day

you thanked answers on my both i.ds so i thought u were talking to me

sorry for disturbing

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