Question

Q) sin 81°-sin99° =​

Answer 1

Answer:

sin 81°-sin99° =sinpetta45 is the answer

Answer 2

Question:-

$\sin \: 81 \degree - \sin \: 99 \degree =$

Solution:-

$\sin \: 81 = \sin \: (90 - 9)$

$\sin \: 99 = \sin \: (90 + 9)$

We have,

$\sin(90 + \theta) = \cos \theta$

$\sin(90 - \theta) = \cos \theta$

So, Question becomes

$\sin(90 - 9) - \sin(90 + 9)$

$= \cos \: 9 - \cos \: 9$

$= 0$

Final Answer:-

$\sin81 \degree - \sin99 \degree = 0$