Business Studies, asked by sallubhai2193, 6 months ago

Q. Small cars get better gas mileage, but they are not as safe as bigger cars. Small cars accounted for 18% of the vehicles on the road, but accidents involving small cars led to 11,898 fatalities during a recent year. Assume the probability a small car is involved in an accident is .18. The probability of an accident involving a small car leading to a fatality is .128 and the probability of an accident not involving a small car leading to a fatality is .05. Suppose you learn of an accident involving a fatality. What is the probability a small car was involved? Assume that the likelihood of getting into an accident is independent of car size.

Answers

Answered by someguy686
1

Answer:

Question

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Small cars get better gas mileage, but they are not as safe as bigger cars. Small cars accounted

for 18% of the vehicles on the road, but accidents involving small cars led to 11,898 fatalities

during a recent year (Reader’s Digest, May 2000). Assume the probability a small car is

involved in an accident is .18. The probability of an accident involving a small car leading to

a fatality is .128 and the probability of an accident not involving a small car leading to a fatality

is .05. Suppose you learn of an accident involving a fatality. What is the probability a

small car was involved? Assume that the likelihood of getting into an accident is independent

of car size.

Explanation

Verified

Step 1

1 of 3

The task states following probabilities in case of traffic accidents :

\begin{gather*} P(\text{small car}) = 0.18\\ P(\text{accident}| \text{ small car}) =0.18\\ P(\text{fatality}| \text{ small car}) =0.128\\ P(\text{fatality}| \text{ not small car}) =0.05\\ \end{gather*}

P(small car)=0.18

P(accident∣ small car)=0.18

P(fatality∣ small car)=0.128

P(fatality∣ not small car)=0.05

 

Use the complement rule to define the probability of not having a small car

\begin{gather*} P(not A) = 1 - P(A) \end{gather*}

P(notA)=1−P(A)

 

Put the known parameters in the rule:

\begin{gather*} P(\text{not small car}) = 1 - P(\text{small car}) =1-0.18=0.82 \end{gather*}

P(not small car)=1−P(small car)=1−0.18=0.82

 

Since the events of accidents are independent of the car size, rule sets following:

\begin{gather*} P(\text{accident}| \text{ small car}) = P(\text{accident}| \text{ not small car})\\ P(\text{accident}| \text{ not small car}) = 0.18 \end{gather*}

P(accident∣ small car)=P(accident∣ not small car)

P(accident∣ not small car)=0.18

 

Bayes' theorem says:

\begin{gather*} P(A_i | B) =\frac{P(A_i)P(B|Ai)}{P(A_1)P(B|A1) + ... + P(A_k)P(B|Ak)} \end{gather*}

P(A  

i

∣B)=  

P(A  

1

)P(B∣A1)+...+P(A  

k

)P(B∣Ak)

P(A  

i

)P(B∣Ai)

 

 

First compute the probability of an accident involving a fatality:

\begin{gather*} P(S)=P(\text{accident}| \text{ small car}) \cdot P(\text{fatality}| \text{ small car}) = 0.18 \cdot 0.128 = 0.02304\\ P(B)=P(\text{accident}| \text{ not small car}) \cdot P(\text{fatality}| \text{ not small car}) = 0.18 \cdot 0.05 = 0.009\\ \end{gather*}

P(S)=P(accident∣ small car)⋅P(fatality∣ small car)=0.18⋅0.128=0.02304

P(B)=P(accident∣ not small car)⋅P(fatality∣ not small car)=0.18⋅0.05=0.009

 

Step 2

2 of 3

Follow the Bayes rule and compute:

\begin{gather*} P(\text{small car }| \text{fatality}) = \frac{P(\text{small car})\cdot P(S)}{P(\text{small car})\cdot P(S) + P(\text{not small car})\cdot P(B)}\\ P(\text{small car }| \text{fatality}) = \frac{0.18\cdot 0.02304}{0.18\cdot 0.02304+0.82\cdot 0.009}\\ P(\text{small car }| \text{fatality}) = \frac{0.0041}{0.0041+0.0074}=0.3571 \end{gather*}

P(small car ∣fatality)=  

P(small car)⋅P(S)+P(not small car)⋅P(B)

P(small car)⋅P(S)

 

P(small car ∣fatality)=  

0.18⋅0.02304+0.82⋅0.009

0.18⋅0.02304

 

P(small car ∣fatality)=  

0.0041+0.0074

0.0041

=0.3571

 

Result

3 of 3

The probability that a small car is involved is 0.3571.

Explanation:

Answered by seelamahit912
0

Answer:

The probability (small car involvement) is 0.3571.

Explanation

Given

Solution

Probability small car=0.18

probability of accidental small car=.18

Probability of not small car=0.05

According to the complement rule, P(NA)=1-P(A)

Probability of not small car=1-Probability of the small car

                         =1-0.18=0.82

As per the question accidents are not based on the size of the car.

P(accident small car)=0.18

P(A/B)=P(B/A)P(A)/P(B)

Probability of involving a fatal accident P(S)=P(accidental small                                                                      

                                                                          car)×P(fatal small car)

                                                                        =0.18×0.128=0.02304

                                                                        =0.18×0.05=0.009

                                                                 p(B)=P(accidental not small                                                                                  

P(small car fatality)=P(small car)×P(S)+P(not small car)×P(B)P(small

                                                                         =car)×P(S)

                                                                          =0.18×0.02304+0.82×.009

                                                                           =0.0041

Probability of small car fatality=0.3571

#SPJ2

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