Question

Q:-solve and find the value of x
2(3x+1)=12+2(4x+3)

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Answer 1

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$\red{\bold{\underline{\underline{QUESTION:-}}}}$

Q:-solve and find the value of x

2(3x+1)=12+2(4x+3)

$\huge\tt\underline\blue{Answer }$

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$⟹2(3x + 1) = 12 + 2(4x + 3)$

$⟹6x + 2 = 12 + 8x + 6$

$⟹2 - 12 - 6 = 8x - 6x$

$⟹ - 16 = 2x$

$⟹ \frac{ - 16}{2} = 2x$

$⟹x = - 8$

CHECK:-

$⟹2(3( - 8) + 1) = 12 + 2(4( - 8) + 3)$

$⟹2( - 24 + 1) = 12 + 2( - 32 + 3)$

$⟹2( - 23) = 12 + 2( - 29)$

$⟹ - 46 = 12 - 58$

$⟹ - 46 = - 46$

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Answer 2

$↝2(3x+1)=12+2(4x+3)$

$↝6x + 2 = 12 + 8x + 6$

$↝2 - 12 - 6 = 8x - 6x$

$↝ - 16 = 2x$

$↝ \frac{ - 16}{2} = 2x$

$↝x = - 8$

verification:-

$↝2(3( - 8) + 1) = 12 + 2(4( - 8) + 3)$

$↝2( - 24 + 1) = 12 + 2( - 32 + 3)$

$↝2( - 23) = 12 + 2( - 29)$

$↝ - 46 = 12 - 58$

$↝ - 46 = - 46.$

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