Question

Q:-solve and find the value of x
2(3x+1)=12+2(4x+3)

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Answer 1

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Q:-solve and find the value of x

2(3x+1)=12+2(4x+3)

$\huge\tt\underline\blue{Answer }$

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$⟹2(3x + 1) = 12 + 2(4x + 3)$

$⟹6x + 2 = 12 + 8x + 6$

$⟹2 - 12 - 6 = 8x - 6x$

$⟹ - 16 = 2x$

$⟹ \frac{ - 16}{2} = 2x$

$⟹x = - 8$

CHECK:-

$⟹2(3( - 8) + 1) = 12 + 2(4( - 8) + 3)$

$⟹2( - 24 + 1) = 12 + 2( - 32 + 3)$

$⟹2( - 23) = 12 + 2( - 29)$

$⟹ - 46 = 12 - 58$

$⟹ - 46 = - 46$

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Answer 2

Answer:

⟹2(3x+1)=12+2(4x+3)

⟹6x + 2 = 12 + 8x + 6⟹6x+2=12+8x+6

⟹2 - 12 - 6 = 8x - 6x⟹2−12−6=8x−6x

⟹ - 16 = 2x⟹−16=2x

⟹ \frac{ - 16}{2} = 2x⟹

2

−16

=2x

⟹x = - 8⟹x=−8

CHECK:-

⟹2(3( - 8) + 1) = 12 + 2(4( - 8) + 3)⟹2(3(−8)+1)=12+2(4(−8)+3)

⟹2( - 24 + 1) = 12 + 2( - 32 + 3)⟹2(−24+1)=12+2(−32+3)

⟹2( - 23) = 12 + 2( - 29)⟹2(−23)=12+2(−29)

⟹ - 46 = 12 - 58⟹−46=12−58

⟹ - 46 = - 46⟹−46=−46