Question

Q:-solve and find the value of x
2(3x+1)=12+2(4x+3)

Answer 1

$\green{\bold{\underline{ ✪ UPSC-ASPIRANT✪ }}}$

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

Q:-solve and find the value of x

2(3x+1)=12+2(4x+3)

$\huge\tt\underline\blue{Answer }$

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$⟹2(3x + 1) = 12 + 2(4x + 3)$

$⟹6x + 2 = 12 + 8x + 6$

$⟹2 - 12 - 6 = 8x - 6x$

$⟹ - 16 = 2x$

$⟹ \frac{ - 16}{2} = 2x$

$⟹x = - 8$

CHECK:-

$⟹2(3( - 8) + 1) = 12 + 2(4( - 8) + 3)$

$⟹2( - 24 + 1) = 12 + 2( - 32 + 3)$

$⟹2( - 23) = 12 + 2( - 29)$

$⟹ - 46 = 12 - 58$

$⟹ - 46 = - 46$

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HOPE IT HELPS YOU..

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Thankyou:)

Answer 2

$\huge \tt{Answer:-}$

$\tt{2(3x + 1) = 12 + 2(4x + 3)}$

$\tt{6x + 2 = 12 + 8x + 6}$

$\tt{2 - 12 - 6 = 8x - 6x}$

$\tt{- 16 = 2x}$

$\tt{\frac{ \cancel{- 16}}{\cancel{2}} =2x }$

$\boxed{\tt{x = - 8}}$

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$\huge \tt{Verification:-}$

$\tt{2(3( - 8) + 1) = 12 + 2(4( - 8) + 3)}$

$\tt{2( - 24 + 1) = 12 + 2( - 32 + 3)}$

$\tt{2( - 23) = 12 + 2( - 29)}$

$\tt{- 46 = 12 - 58}$

$\tt{- 46 = - 46}$

$\tt{As, \: L.H.S. = R.H.S. }$

$\tt{Hence, \: Proved ✌︎}$