Math, asked by Anonymous, 7 months ago

Q:-solve and verify the equation
 \frac{1}{2} - \frac{1}{3} (x - 1) + 2 = 0

Answers

Answered by Anonymous
26

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Q:-solve and verify the equation

 \frac{1}{2} - \frac{1}{3} (x - 1) + 2 = 0

\huge\tt\underline\blue{Answer }

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⟹ \frac{1}{2}  -  \frac{1}{3} (x - 1) + 2 = 0</p><p>

⟹</p><p> \frac{3 - 2(x - 1) + 2}{6}  = 0

⟹</p><p> \frac{1}{6} (x - 1) + 2 = 0

⟹</p><p>(x - 1) + 2 = 0

⟹</p><p>x - 1 =  - 2

⟹</p><p>x =  - 2 + 1

⟹</p><p>x =  - 1

CHECK:-

⟹ \frac{1}{2}  -  \frac{1}{3} ( - 1 - 1) + 2</p><p>

⟹</p><p> \frac{3 - 2( - 2) + 2}{6}  = 0

⟹</p><p> \frac{1}{6} ( - 2) + 2 = 0

⟹</p><p> \frac{0}{6}  = 0

⟹</p><p>0 = 0

THEREFORE,L.H.S=R.H.S

VERIFIED ✓

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HOPE IT HELPS YOU..

_____________________

Thankyou:)

Answered by Anonymous
1

\huge\tt\underline\red{Answer }

 \tt{⟹ \frac{1}{2} - \frac{1}{3} (x - 1) + 2 = 0}

 \tt{⟹ \frac{1}{6} (x - 1) + 2 = 0}

 \tt{⟹ (x - 1) + 2 = 0}

 \tt{⟹ x - 1 = - 2}

 \tt{⟹ x = - 2 + 1}

 \tt{⟹ x = - 1}

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