Question

Q:-solve and verify the equation
$\frac{1}{2} - \frac{1}{3} (x - 1) + 2 = 0$

Aryabhatta was a great mathematician​

Answer 1

Step-by-step explanation:

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

Q:-solve and verify the equation

$\frac{1}{2} - \frac{1}{3} (x - 1) + 2 = 0$

$\huge\tt\underline\blue{Answer }$

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$⟹ \frac{1}{2} - \frac{1}{3} (x - 1) + 2 = 0</p><p>$

$⟹</p><p> \frac{3 - 2(x - 1) + 2}{6} = 0$

$⟹</p><p> \frac{1}{6} (x - 1) + 2 = 0$

$⟹</p><p>(x - 1) + 2 = 0$

$⟹</p><p>x - 1 = - 2$

$⟹</p><p>x = - 2 + 1$

$⟹</p><p>x = - 1$

CHECK:-

$⟹ \frac{1}{2} - \frac{1}{3} ( - 1 - 1) + 2</p><p>$

$⟹</p><p> \frac{3 - 2( - 2) + 2}{6} = 0$

$⟹</p><p> \frac{1}{6} ( - 2) + 2 = 0$

$⟹</p><p> \frac{0}{6} = 0$

$⟹</p><p>0 = 0$

THEREFORE,L.H.S=R.H.S

VERIFIED ✔️

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HOPE IT HELPS YOU..

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Thankyou:)

Answer 2

Step-by-step explanation:

f(x) = kx³ – 8x² + 5

Roots are α – β , α & α +β

Sum of roots = – (-8)/k

Sum of roots = α – β + α + α +β = 3α

= 3α = 8/k

= k = 8/3α

or we can solve as below

f(x) = (x – (α – β)(x – α)(x – (α +β))

= (x – α)(x² – x(α+β + α – β) + (α² – β²))

= (x – α)(x² – 2xα + (α² – β²))

= x³ – 2x²α + x(α² – β²) – αx² +2α²x – α³ + αβ²

= x³ – 3αx² + x(3α² – β²) + αβ² – α³

= kx³ – 3αkx² + xk(3α² – β²) + k(αβ² – α³)

comparing with

kx³ – 8x² + 5

k(3α² – β²) = 0 => 3α² = β²

k(αβ² – α³) = 5

=k(3α³ – α³) = 5

= k2α³ = 5

3αk = 8 => k = 8/3α

(8/3α)2α³ = 5

=> α² = 15/16

=> α = √15 / 4