Q Solve for X and Y
bX - aY+a+b=0;
bX-ay+2ab=0
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= ( b2 × - a2y + a2b + ab 2 ) / ab =0 and ( bx ) - ( ay ) + 2ab = 0
= ( b2x - azy + a2b + ab 2 ) = 0 .........
= ( 1 )
= ( bx ) - ( ay ) + 2ab = 0 ......... ( 2 )
Multiply equation ( 2 ) by b
( b2 x ) - ( aby ) + 2ab 2 = 0........
= ( 3 )
Substract ( 3 )from ( 1 )
= a2y + aby + a2b + ab2 - 2ab2 = 0
= y ( ab - a2 ) = ab2 - a2b
= ya (b - a ) = ab ( b - a )
= y = b
Sub y = b is equation ( 2 )
We get ( bx ) - ( ab ) + 2ab = 0
= b ( x + a ) = 0
= x + a = 0
= x = -a and y = b
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