Question

Q- solve the following equation and verify the solution ....

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Answer 1

(i)

Let's solve your equation step-by-step.

$x+\frac{6}{4} =5\frac{3}{4}$

Step 1: Simplify both sides of the equation.

⇒ $x+\frac{6}{4} =5\frac{3}{4}$

⇒ $x+\frac{3}{2} =\frac{23}{4}$

Step 2: Subtract $\frac{3}{2}$ from both sides.

⇒ $x+\frac{3}{2} - \frac{3}{2}=\frac{23}{4} - \frac{3}{2}$

⇒$x = \frac{17}{4}$

Let's verify the value of 'x'.

⇒ $x+\frac{6}{4} =5\frac{3}{4}$

⇒ $\frac{17}{4} +\frac{6}{4} =5\frac{3}{4}$

⇒ $\frac{23}{4} =5\frac{3}{4}$

⇒ $5\frac{3}{4} =5\frac{3}{4}$

$\bf \therefore x = \frac{17}{4} \ in \ the \ equation => \ x+\frac{6}{4} =5\frac{3}{4}$

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(ii)

Let's solve your equation step-by-step.

$\frac{x}{5} +11=\frac{1}{15}$

Step 1: Simplify both sides of the equation.

⇒ $\frac{x}{5} +11=\frac{1}{15}$

⇒ $\frac{1}{5}x +11=\frac{1}{15}$

Step 2: Subtract 11 from both sides.

⇒ $\frac{1}{5}x +11-11=\frac{1}{15}-11$

⇒ $\frac{1}{5}x = \frac{-164}{15}$

Step 3: Multiply both sides by 5.

⇒ $5\times \frac{1}{5}x = 5\times \frac{-164}{15}$

⇒ $x = \frac{-164}{3}$

Let's verify the value of 'x'.

⇒ $\frac{x}{5} +11=\frac{1}{15}$

⇒ $\dfrac{\frac{-164}{3} }{5} +11=\frac{1}{15}$

⇒ $\frac{-164}{15}+11=\frac{1}{15}$

⇒ $\frac{1}{15}=\frac{1}{15}$

$\bf \therefore x = \frac{-164}{3} \ in \ the \ equation => \ \frac{x}{5} +11 =\frac{1}{15}$

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