Question

Q. Solve the following with identities:
(2x+1/x-3)^2

Answer 1

Answer:

${(2x + \frac{1}{x} - 3)}^{2}$

Using identity

↪ (a + b + c)² = a² + b² + c² + 2ab - 2bc - 2ac

${(2x)}^{2} + { (\frac{1}{x}) }^{2} + {( - 3)}^{2} + 2(2x)( \frac{1}{x} ) - 2( \frac{1}{x} )( - 3) - 2( - 3)(2x)$

$4 {x}^{2} + \frac{1}{ {x}^{2} } + 9 + (4) -( \frac{ - 6}{x} ) - ( - 12x)$

$4 {x}^{2} + \frac{1}{ {x}^{2} } + 13 + \frac{6}{x} + 12$