Question

Q. solve the given simultaneous equation.
1. 8x + 3y= 11 ; 3x - y = 2


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Answer 1

Equation 1 :

$8x + 3y = 11$

Equation 2 :

$3x - y = 2$

Multiply Equation 2 by 3 ;

(Equation 3) :

$9x - 3y = 6$

Add Equation 3 and Equation 2,

$\: \: \: \: \: \: \: \: \: 8x + 3y = 11 \\ \: + \: \: \: 9x - 3y = 6$

$17x = 17 \\ x = \frac{17}{17} \\ x = 1 \:$

Put x = 1 in Equation 1,

$8x + 3y = 11 \\ 8(1) + 3y = 11 \\ 8 + 3y = 11 \\ 3y = 11 - 8 \\ 3y = 3 \\ y = \frac{3}{3} \\ y = 1$

Therefore, The Value of $x = 1$

And $y = 1$

$\huge\sf\implies{Thanks : ❤}$

Answer 2

Answer:

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