Math, asked by Anonymous, 7 months ago

Q:-solve the quadratic equation
 \sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0

Answers

Answered by Anonymous
7

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Q:-solve the quadratic equation

 \sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0

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------>>>>Here is your answer<<<<--------

⇛ \sqrt{2}  {x}^{2}  + 7x + 5 \sqrt{2}  = 0

⇛ \sqrt{2}  {x}^{2}  + 2x + 5x + 5 \sqrt{2}  = 0

 ⇛ \sqrt{2} x(x +  \sqrt{2} ) + 5(x +  \sqrt{2} ) = 0

⇛(x +  \sqrt{2} )( \sqrt{2} x + 5)

⇛x +  \sqrt{2}  = 0

⇛x =  -  \sqrt{2} ✓

⇛ \sqrt{2} x + 5 = 0

⇛x =  -  \frac{5}{ \sqrt{2} } ✓

HOPE IT HELPS YOU..

_____________________

Thankyou:)

Answered by dezisantosh
7

Answer:

⇛2x2+7x+52=0

⇛ \sqrt{2} {x}^{2} + 2x + 5x + 5 \sqrt{2} = 0⇛2x2+2x+5x+52=0

⇛ \sqrt{2} x(x + \sqrt{2} ) + 5(x + \sqrt{2} ) = 0⇛2x(x+2)+5(x+2)=0

⇛(x + \sqrt{2} )( \sqrt{2} x + 5)⇛(x+2)(2x+5)

⇛x + \sqrt{2} = 0⇛x+2=0

⇛x = - \sqrt{2} ✓⇛x=−2✓

⇛ \sqrt{2} x + 5 = 0⇛2x+5=0

⇛x = - \frac{5}{ \sqrt{2} } ✓⇛x=−25✓

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