Q:-solve the quadratic equation
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Q:-solve the quadratic equation
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Answered by
7
Answer:
⇛2x2+7x+52=0
⇛ \sqrt{2} {x}^{2} + 2x + 5x + 5 \sqrt{2} = 0⇛2x2+2x+5x+52=0
⇛ \sqrt{2} x(x + \sqrt{2} ) + 5(x + \sqrt{2} ) = 0⇛2x(x+2)+5(x+2)=0
⇛(x + \sqrt{2} )( \sqrt{2} x + 5)⇛(x+2)(2x+5)
⇛x + \sqrt{2} = 0⇛x+2=0
⇛x = - \sqrt{2} ✓⇛x=−2✓
⇛ \sqrt{2} x + 5 = 0⇛2x+5=0
⇛x = - \frac{5}{ \sqrt{2} } ✓⇛x=−25✓
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