Question

Q:-solve the quadratic equation
$\sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0$
find the value of x ​

Answer 1

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$\red{\bold{\underline{\underline{QUESTION:-}}}}$

Q:-solve the quadratic equation

$\sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0$

$\huge\tt\underline\blue{ANSWER }$

------>>>>Here is your answer<<<<--------

$⇛ \sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0$

$⇛ \sqrt{2} {x}^{2} + 2x + 5x + 5 \sqrt{2} = 0$

$⇛ \sqrt{2} x(x + \sqrt{2} ) + 5(x + \sqrt{2} ) = 0$

$⇛(x + \sqrt{2} )( \sqrt{2} x + 5)$

$⇛x + \sqrt{2} = 0$

$⇛x = - \sqrt{2} ✓$

$⇛ \sqrt{2} x + 5 = 0$

$⇛x = - \frac{5}{ \sqrt{2} } ✓$

HOPE IT HELPS YOU..

_____________________

Thankyou:)

Answer 2

Answer:

Step-by-step explanation:

Given,

2

​  

x  

2

+7x+5  

2

​  

=0

or,  

2

​  

x  

2

+2x+5x+5  

2

​  

=0

or, x  

2

​  

(x+  

2

​  

)+5(x+  

2

​  

)=0

or, (x  

2

​  

+5)(x+  

2

​  

)=0

⇒x=−  

2

​  

 

5

​  

,−  

2

​  

.