Question

Q:-solve the quadratic equation
$\sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0$solve and find out the value of x using factorisation method​

Answer 1

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$\red{\bold{\underline{\underline{QUESTION:-}}}}$

Q:-solve the quadratic equation

$\sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0$

$\huge\tt\underline\blue{ANSWER }$

------>>>>Here is your answer<<<<--------

$⇛ \sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0$

$⇛ \sqrt{2} {x}^{2} + 2x + 5x + 5 \sqrt{2} = 0$

$⇛ \sqrt{2} x(x + \sqrt{2} ) + 5(x + \sqrt{2} ) = 0$

$⇛(x + \sqrt{2} )( \sqrt{2} x + 5)$

$⇛x + \sqrt{2} = 0$

$⇛x = - \sqrt{2} ✓$

$⇛ \sqrt{2} x + 5 = 0$

$⇛x = - \frac{5}{ \sqrt{2} } ✓$

HOPE IT HELPS YOU..

_____________________

Thankyou:)

Answer 2

Step-by-step explanation:

Given,

2

x

2

+7x+5

2

=0

or,

2

x

2

+2x+5x+5

2

=0

or, x

2

(x+

2

)+5(x+

2

)=0

or, (x

2

+5)(x+

2

)=0

⇒x=−

2

5

,−

2

.

These are the required roots.

Hope it helps you

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