Question

Q. solve the quadratic equation:
$\sqrt{3x { }^ {2} } + 10x + 7 \sqrt{3 } = 0$
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Answer 1

Step-by-step explanation:

$\sqrt{3} {x}^{2} + 10x + 7 = 0 \\ D= {b}^{2} -4ac \\ = {10}^{2} - 4 \times \sqrt{3} \times 7 \\ = 100 - 28 \sqrt{3} \\ = 4(25 - 7 \sqrt{3}) \\ = >have \: two \: different \: roots \\ x = \frac{ - b± \sqrt{D} }{2a} \\ x = \frac{ - 10± \sqrt{4(25 - 7 \sqrt{3}) } }{ 2\sqrt{3} } \\ x = \frac{ - 10± 2\sqrt{25 - 7 \sqrt{3} } }{2 \sqrt{3} } \\ x = \frac{2 (- 5± \sqrt{25 - 7 \sqrt{3} } )}{2 \sqrt{3} } \\ x = \frac{ - 5± \sqrt{25 - 7 \sqrt{3} } }{ \sqrt{3} } \\ x = \frac{ - 5+ \sqrt{25 - 7 \sqrt{3} } }{ \sqrt{3} }, \: \frac{ - 5- \sqrt{25 - 7 \sqrt{3} } }{ \sqrt{3} }$

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