Q:-solve this equation and also verify........._______........
Answers
Answer:
Given equation is x 2/3 + x 1/3 - 2 = 0
Putting x 1/3 = y, the given equation becomes
y2 + y – 2 = 0
⇒ y2 + 2y – y – 2 = 0
⇒ y(y+ 2) – 1(y + 2) = 0
⇒ (y + 2) (y – 1) = 0
⇒ y + 2 = 0 or y – 1 = 0
⇒ y = -2 or y = 1
But x 1/3 = y
∴ x 1/3 = - 2 or x 1/3 = 1
⇒ x = (- 2)3 or x = (1)3
⇒ x = - 8 or x = 1
Hence, roots are -8, 1.
Working out:
Here we are provided with an equation in variable x. And we have to find the value of this variable x in this equation.
GiveN:
So, let's start solving the above equation and understand the steps of solving to reach the final result.
Opening the parentheses,
Now combining and adding the constant and the like terms in this equation:
Now we have to find x, so let's flip the equation:
We know that inverse of division is multiplication, hence we can multiply 3 in RHS,
Hence the required value for x is:
And we are done !!
Quick verification:
Let's plug in the value of x in the equation,
Here, LHS = RHS
✤ Hence, verified !!