Question

Q). sovle : x+2/6-(11-x/3-1/4)=3x-4/12 ?

$\pmb{\frak\red{\underline{•Don't~Spam}}$​

Answer 1

Step-by-step explanation:

refer to the attachment

hope it helps you

Answer 2

${\sf{\bf{Given}~:~\sf{\dfrac{x~ + ~2}{6} ~- ~\bigg(\dfrac{11~ -~ x}{3}~ -~ \dfrac{1}{4}\bigg) ~= ~\dfrac{3x~ - ~4}{12}}}}$

To Find : Find the Value of x ?

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Solution : Let the considered value be x

$~$

$\qquad\qquad{\sf:\implies{\dfrac{x + 2}{6} ~-~ \bigg(\dfrac{11~ - ~x}{3}~ - ~\dfrac{1}{4}\bigg) ~= ~\dfrac{3x ~- ~4}{12}}}$

$\qquad\qquad{\sf:\implies{\dfrac{x~ + ~2}{6} ~- ~\bigg(\dfrac{4(11~ - ~x) ~-~ 3}{12}\bigg)~=~\dfrac{3x~ - ~4}{12}}}$

$\qquad\qquad{\sf:\implies{\dfrac{x ~+ ~2}{6}~ - ~\bigg(\dfrac{44~-~4x ~-~ 3}{12}\bigg)~=~\dfrac{3x~ - ~4}{12}}}$

$\qquad\qquad{\sf:\implies{\dfrac{x ~+ ~2}{6}~ - ~\bigg(\dfrac{41~-~4x}{12}\bigg)~=~\dfrac{3x~ - ~4}{12}}}$

$\qquad\qquad{\sf:\implies{\bigg(\dfrac{x~+~2}{6}~-~\dfrac{(41~-~4x)}{12}\bigg)~=~\dfrac{3x~ - ~4}{12}}}$

$\qquad\qquad{\sf:\implies{\dfrac{2(x~+~2)~-~(41~-~4x)}{12}~=~\dfrac{3x~ - ~4}{12}}}$

$\qquad\qquad{\sf:\implies{\dfrac{2x~+~4~-~41~+~4x}{12}~=~\dfrac{3x~ - ~4}{12}}}$

$\qquad\qquad{\sf:\implies{\dfrac{- 37~+~6x}{12}~=~\dfrac{3x~ - ~4}{12}}}$

$\qquad\qquad{\sf:\implies{- 37~+~6x~=~3x~-~4}}$

$\qquad\qquad{\sf:\implies{6x~-~3x~=~37~-~4}}$

$\qquad\qquad{\sf:\implies{3x~=~33}}$

$\qquad\qquad{\sf:\implies{x~=~\cancel\dfrac{33}{3}}}$

$\qquad\qquad:\implies{\underline{\boxed{\frak{\pink{x~=~11}}}}}$★

$~$

Hence,

$\therefore\underline{\sf{The ~value ~of~\bf{\underline{x}}~\sf{is}~\bf{\underline{11}}}}$