Question

Q)Starting from rest, a cyclist moving at a uniform acceleration attains a velocity of 60m/s in 300
seconds. If he applies brake and slows down to rest at the rate of 2m/s?. Find
(a) the acceleration in first 200 seconds
(b) the time taken to come to rest in deceleration.
(c) The displacement in the whole journey
PLEASE GIVE THE WHOLE ANSWER OR I WILL REPORT YOU​

Answer 1

Answer:

Explanation:

a) v = 60 m/s

   u = 0

   t = 300 sec

   v = u+at

    so, a = 60-0/300

a =  0.2 m/s^2

If u read the question properly , you would have marked that acceleration is uniform.

yes so, a=0.2 m/s2

b) Since the cyclist applies brake,

v = 0 , u = 60m/s(here) and a= - 2m/s(minus sign for deceleration.)

Again using   v = u+at;

we'll get --- 60= 2t and thus t= 30 sec

c) v^2- u^2 = 2as (s is displacement.)  

0- 3600 = 2 (-2s)  (Don't forget decelaration rate is given to us as 2.)

Hence, Displacement= 900 m

:) :) Do trust the answerer , not everyone gives the half answer.

Answer 2

Explanation:

here is ur ans hope it helps in a good way